The solution of two linear equations is (-2,2). One equations has a slope of 3. The slope of the other equation is the negative reciprocal of the slope of the first.The system described above is represented by the following equations.

The system of equations is:[tex]3x-y=-8[/tex][tex]x+3y=4[/tex]Step-by-step explanation:Let the line 1 be: [tex]l_1[/tex]Let line 2 be: [tex]l_2[/tex]Both lines will pass through the same point (-2,2)AndGiven[tex]m_1=3\\m_2=-\frac{1}{3}[/tex]The slope intercept form for first line will be:[tex]y=m_1x+b[/tex]Putting values[tex]y=3x+b[/tex]Putting the point in the equation[tex]2=(-2)(3)+b\\2=-6+b\\b=2+6\\b=8[/tex]So, the equation is: y=3x+8Converting the equation in standard form[tex]y=3x+8[/tex]Subtracting y from both sides[tex]0=3x-y+8[/tex]Subtracting 8 from both sides[tex]3x-y=-8[/tex]The second line's equation will be:[tex]y=m_2x+b[/tex]Putting slope[tex]y=-\frac{1}{3}x+b[/tex]Putting the point[tex]2=-\frac{1}{3}(-2)+b\\2=\frac{2}{3}+b\\b=2-\frac{2}{3}\\b=\frac{6-2}{3}\\b=\frac{4}{3}[/tex]The equation is:[tex]y=-\frac{1}{3}x+\frac{4}{3}[/tex]Converting the equation in standard formMultiplying whole equation by 3[tex]3y=-x+4[/tex]Adding x on both sides[tex]x+3y=4[/tex]HenceThe system of equations is:[tex]3x-y=-8[/tex][tex]x+3y=4[/tex]Keywords: Equation of line, Linear equationLearn more about linear equation at:brainly.com/question/2116906brainly.com/question/2131336#LearnwithBrainly