2. How much water could my well hold if the depth of the well is 30ft and the diameter of the well is 24ft?
Accepted Solution
A:
Answer:[tex]V=4,320\pi\ ft^{3}[/tex] or [tex]V=13,564.8\ ft^{3}[/tex]Step-by-step explanation:we know thatThe volume of the cylinder (the well) is equal to[tex]V=\pi r^{2} h[/tex]where[tex]r=24/2=12\ ft[/tex] ----> the radius is half the diameter[tex]h=30\ ft[/tex]substitute[tex]V=\pi (12)^{2}(30)[/tex][tex]V=4,320\pi\ ft^{3}[/tex]assume[tex]\pi =3.14[/tex][tex]V=4,320(3.14)=13,564.8\ ft^{3}[/tex]